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CH3-overset(O)overset(||)Cunderset(a)(-)...

`CH_3-overset(O)overset(||)Cunderset(a)(-)Ounderset(b)(-)CH_3` ,
The correct relation between the bond lengths a and b is:

A

`a=b`

B

`bgta`

C

`blta`

D

Impossible to predict

Text Solution

AI Generated Solution

The correct Answer is:
To determine the correct relationship between the bond lengths \( a \) and \( b \) in the compound \( CH_3-C(=O)-O-CH_3 \), we will analyze the structure and the effects of resonance on the bonds. ### Step-by-Step Solution: 1. **Identify the Structure**: The given compound is \( CH_3-C(=O)-O-CH_3 \). Here, we have a carbonyl group (C=O) connected to an oxygen atom, which is further connected to another methyl group (CH3). 2. **Label the Bonds**: - Let bond \( a \) be the bond between carbon (C) and oxygen (O) in the carbonyl group (C=O). - Let bond \( b \) be the bond between carbon (C) and oxygen (O) in the ether part (C-O). 3. **Understand Resonance**: The structure can exhibit resonance. The lone pairs on the oxygen can participate in resonance by forming a double bond with the carbon, leading to different resonance structures. This means that the C-O bond can exhibit double bond character due to resonance. 4. **Analyze Bond Character**: - In the carbonyl bond (C=O), the bond is a double bond, which is typically shorter and stronger than a single bond. - In the ether bond (C-O), it is a single bond, which is longer and weaker compared to a double bond. 5. **Compare Bond Lengths**: - Since bond \( a \) (C=O) has double bond character, it will be shorter than bond \( b \) (C-O), which is a single bond. - Therefore, the bond length of \( a \) is less than the bond length of \( b \). 6. **Conclusion**: The correct relationship between the bond lengths is: \[ b > a \]

To determine the correct relationship between the bond lengths \( a \) and \( b \) in the compound \( CH_3-C(=O)-O-CH_3 \), we will analyze the structure and the effects of resonance on the bonds. ### Step-by-Step Solution: 1. **Identify the Structure**: The given compound is \( CH_3-C(=O)-O-CH_3 \). Here, we have a carbonyl group (C=O) connected to an oxygen atom, which is further connected to another methyl group (CH3). 2. **Label the Bonds**: ...
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