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Most stable carbocation among the follow...

Most stable carbocation among the following is :

A

B

C

D

`""^(o+)CH_3`

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To determine the most stable carbocation among the given options, we need to analyze the degree of each carbocation. The stability of carbocations is generally ranked as follows: 1. Tertiary (3°) carbocations - most stable 2. Secondary (2°) carbocations - moderately stable 3. Primary (1°) carbocations - less stable 4. Methyl carbocation - least stable ### Step-by-Step Solution: **Step 1: Identify the types of carbocations in the options.** - Look at each option and determine how many carbon atoms are attached to the positively charged carbon atom. **Step 2: Classify each carbocation.** - For each option: - If the positively charged carbon is attached to three other carbon atoms, it is a tertiary (3°) carbocation. - If it is attached to two carbon atoms, it is a secondary (2°) carbocation. - If it is attached to one carbon atom, it is a primary (1°) carbocation. - If it is attached to no carbon atoms (only hydrogens), it is a methyl carbocation. **Step 3: Compare the stability of the carbocations.** - Based on the classification: - Tertiary (3°) carbocations are the most stable. - Secondary (2°) carbocations are less stable than tertiary but more stable than primary. - Primary (1°) carbocations are less stable than secondary. - Methyl carbocations are the least stable. **Step 4: Determine the most stable carbocation.** - From the analysis, identify which option corresponds to the tertiary carbocation, as it will be the most stable. ### Conclusion: - The most stable carbocation among the options provided is the tertiary (3°) carbocation.

To determine the most stable carbocation among the given options, we need to analyze the degree of each carbocation. The stability of carbocations is generally ranked as follows: 1. Tertiary (3°) carbocations - most stable 2. Secondary (2°) carbocations - moderately stable 3. Primary (1°) carbocations - less stable 4. Methyl carbocation - least stable ### Step-by-Step Solution: ...
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