Select the response that correctly identifies the number of carbon atoms of each type of hybridization in the compound given below
`H_2 C = C = CH - CH = O`

Options

A. `{:(sp^3,sp^2,sp),(2,2,0):}`
B. `{:(sp^3,sp^2,sp),(1,3,0):}`
C. `{:(sp^3,sp^2,sp),(0,3,1):}`
D. `{:(sp^3,sp^2,sp),(1,2,1):}`

Answer

To determine the number of carbon atoms of each type of hybridization in the compound \( H_2C = C = CH - CH = O \), we will follow these steps:

### Step 1: Identify the Structure
The compound can be represented as follows:
```
H H
\ /
C
||
C
/ \
C C
| ||
H O
```
This shows that we have a carbon chain with double bonds and a carbonyl group (C=O).

### Step 2: Assign Hybridization
To find the hybridization of each carbon atom, we will calculate the steric number (SN) for each carbon. The steric number is calculated as:
\[ \text{Steric Number} = \text{Number of Sigma Bonds} + \text{Number of Lone Pairs} \]

- **Carbon 1 (C1)**:
- Attached to 2 H atoms (2 sigma bonds) and 1 C atom (1 sigma bond).
- Total sigma bonds = 2 + 1 = 3.
- Steric Number = 3 (no lone pairs).
- Hybridization = SP².

- **Carbon 2 (C2)**:
- Attached to 1 C atom (1 sigma bond) and 1 C atom (1 sigma bond).
- Total sigma bonds = 1 + 1 = 2.
- Steric Number = 2 (no lone pairs).
- Hybridization = SP.

- **Carbon 3 (C3)**:
- Attached to 1 C atom (1 sigma bond), 1 C atom (1 sigma bond), and 1 H atom (1 sigma bond).
- Total sigma bonds = 1 + 1 + 1 = 3.
- Steric Number = 3 (no lone pairs).
- Hybridization = SP².

- **Carbon 4 (C4)**:
- Attached to 1 C atom (1 sigma bond), 1 H atom (1 sigma bond), and 1 O atom (1 sigma bond).
- Total sigma bonds = 1 + 1 + 1 = 3.
- Steric Number = 3 (no lone pairs).
- Hybridization = SP².

### Step 3: Count the Hybridized Carbons
Now, we will summarize the hybridization of each carbon:
- C1: SP²
- C2: SP
- C3: SP²
- C4: SP²

### Step 4: Total Count
- **SP³ hybridized carbon atoms**: 0
- **SP² hybridized carbon atoms**: 3 (C1, C3, C4)
- **SP hybridized carbon atoms**: 1 (C2)

### Final Answer
The number of carbon atoms of each type of hybridization in the compound \( H_2C = C = CH - CH = O \) is:
- SP³: 0
- SP²: 3
- SP: 1