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underset((I))(CH2)=Oharrunderset((II))("...

`underset((I))(CH_2)=Oharrunderset((II))(""^(o+)CH_2)-O^(Theta)harrunderset((III))(""^(Theta)CH_2)-O^(o+)`
Which of these structures is practically not a valid canonical structure for formaldehyde ?

A

I

B

II

C

III

D

None of these

Text Solution

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The correct Answer is:
To determine which of the given structures is not a valid canonical structure for formaldehyde, we need to analyze each of the three structures provided: 1. **Structure I: CH₂=O** This structure represents formaldehyde in its standard form. It has a carbon atom double-bonded to an oxygen atom and single-bonded to two hydrogen atoms. This is a valid canonical structure as it follows the rules of valency and stability. 2. **Structure II: CH₂⁺O⁻** In this structure, the carbon atom is bonded to two hydrogen atoms and has a positive charge, while the oxygen atom carries a negative charge. The negative charge on oxygen is acceptable because oxygen is more electronegative than carbon, making this structure a valid canonical form. 3. **Structure III: CH₂⁻O⁺** Here, the carbon atom is bonded to two hydrogen atoms and carries a negative charge, while the oxygen atom has a positive charge. This structure is problematic because it places a positive charge on oxygen, which is highly electronegative. Electronegativity dictates that negative charges are more stable on electronegative atoms, while positive charges are more stable on less electronegative atoms. Therefore, this structure is not a valid canonical structure. Based on this analysis, we conclude that: **The structure that is practically not a valid canonical structure for formaldehyde is Structure III (CH₂⁻O⁺).**
To determine which of the given structures is not a valid canonical structure for formaldehyde, we need to analyze each of the three structures provided: 1. **Structure I: CH₂=O** This structure represents formaldehyde in its standard form. It has a carbon atom double-bonded to an oxygen atom and single-bonded to two hydrogen atoms. This is a valid canonical structure as it follows the rules of valency and stability. 2. **Structure II: CH₂⁺O⁻** In this structure, the carbon atom is bonded to two hydrogen atoms and has a positive charge, while the oxygen atom carries a negative charge. The negative charge on oxygen is acceptable because oxygen is more electronegative than carbon, making this structure a valid canonical form. ...
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