Find out the total number of stereoisomers of the given following compound.
`Cl-CH=CH-underset(H)underset(|)overset(Cl)overset(|)(C)-CH=CH-Cl`

Explanation

To find the total number of stereoisomers for the given compound `Cl-CH=CH-underset(H)underset(|)overset(Cl)overset(|)(C)-CH=CH-Cl`, we can follow these steps:

### Step 1: Identify the Stereocenters
First, we need to identify the stereocenters in the compound. A stereocenter is a carbon atom that has four different substituents or groups attached to it.

- In the given compound, we have two double bonds (C=C), and we need to check if they can create stereocenters.
- The first double bond (C1=C2) has two different substituents (Cl and H) on one side and two identical groups (C) on the other side, which does not create a stereocenter.
- The second double bond (C3=C4) also has two identical groups (Cl) on one side and two different groups (C and H) on the other side, which also does not create a stereocenter.

However, we can see that the compound is unsymmetrical due to the presence of different substituents.

### Step 2: Determine the Number of Stereocenters (N)
From our analysis, we can identify that there are two stereocenters in the compound:

- **C1** has Cl and H as different substituents.
- **C3** has Cl and H as different substituents.

Thus, we have **N = 2** stereocenters.

### Step 3: Calculate the Total Number of Stereoisomers
To calculate the total number of stereoisomers, we can use the formula:

\[ \text{Total Stereoisomers} = 2^N \]

Substituting the value of N:

\[ \text{Total Stereoisomers} = 2^2 = 4 \]

### Final Answer
The total number of stereoisomers for the given compound is **4**.

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