The IUPAC name of`CH_3 - underset(H)underset(|) overset(OH)overset(|) C - CH_2 - overset(O)overset(||) C - CH_3` is

Options

A. 2-Hydroxypentan-4-one
B. 4-Hydroxypentan-2-one
C. 4-oxopentan-2-ol
D. 2-oxopentan-4-ol

Explanation

To determine the IUPAC name of the compound `CH₃ - H - OH - C - CH₂ - O - C - CH₃`, we will follow a systematic approach:

### Step 1: Identify the Longest Carbon Chain
The first step in naming a compound is to identify the longest continuous carbon chain. In this case, the longest chain consists of 5 carbon atoms.

### Step 2: Determine the Functional Groups
In this compound, there are two functional groups: a ketone (C=O) and an alcohol (–OH). According to IUPAC rules, the ketone has a higher priority than the alcohol when it comes to naming.

### Step 3: Number the Carbon Chain
Next, we need to number the carbon atoms in the chain. The numbering should start from the end closest to the functional group with the highest priority (the ketone). Thus, we number the carbon atoms as follows:
1. C1 - Carbon with the ketone group (C=O)
2. C2 - Next carbon
3. C3 - Next carbon
4. C4 - Carbon with the alcohol group (–OH)
5. C5 - Last carbon

### Step 4: Identify the Substituents and Their Positions
From the numbering:
- The ketone group is on carbon 2.
- The alcohol group (hydroxy) is on carbon 4.

### Step 5: Construct the Name
Now, we can construct the IUPAC name:
- The base name for a 5-carbon chain is "pentane."
- The ketone group at carbon 2 is denoted by the suffix "on."
- The alcohol group at carbon 4 is denoted by the prefix "hydroxy."

Putting it all together, we have:
- The name is "4-hydroxy-2-pentanone."

### Final IUPAC Name
Thus, the IUPAC name of the compound is **4-hydroxy-2-pentanone**.

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