The number of isomers possible with molecular formula
`C_(2)H_(4)Cl_(2)` is :

Options

A. 2
B. 3
C. 4
D. 6

Explanation

To determine the number of isomers possible with the molecular formula \( C_2H_4Cl_2 \), we can follow these steps:

### Step 1: Identify the Structure
The molecular formula \( C_2H_4Cl_2 \) indicates that we have 2 carbon atoms, 4 hydrogen atoms, and 2 chlorine atoms. We can start by drawing the basic structure of the compound, which is ethane (C-C).

### Step 2: Determine Possible Isomers
Isomers are compounds that have the same molecular formula but different structural arrangements. For \( C_2H_4Cl_2 \), we can consider the following arrangements:

1. **1,2-Dichloroethane**: In this structure, one chlorine atom is attached to each of the two carbon atoms. This can be represented as:
- Cl-CH2-CHCl-H

2. **1,1-Dichloroethane**: In this structure, both chlorine atoms are attached to the same carbon atom. This can be represented as:
- Cl2-CH2-H

### Step 3: Count the Isomers
From the arrangements identified:
- **1,2-Dichloroethane**: One chlorine on each carbon.
- **1,1-Dichloroethane**: Both chlorines on one carbon.

Thus, we find that there are **2 distinct isomers** for the molecular formula \( C_2H_4Cl_2 \).

### Final Answer
The number of isomers possible with the molecular formula \( C_2H_4Cl_2 \) is **2**.

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