The simplest alcohol that can exhibit enantiomerism:

Options

A. 1-propanol
B. 2-butanol
C. 2-propanol
D. 1-butanol

Explanation

To determine the simplest alcohol that can exhibit enantiomerism, we need to identify the alcohol that contains a chiral carbon atom. A chiral carbon is a carbon atom that is bonded to four different groups, leading to non-superimposable mirror images.

### Step-by-Step Solution:

1. **Understanding Chiral Centers**:
- A chiral center (or chiral carbon) is a carbon atom that is attached to four different substituents. This configuration allows for the existence of two enantiomers (non-superimposable mirror images).

2. **Analyzing Different Alcohols**:
- We will evaluate several simple alcohols to find one that has a chiral carbon.

3. **1-Propanol**:
- Structure: CH3-CH2-CH2OH
- Analysis: The carbon atoms in 1-propanol do not have four different substituents. Therefore, it does not have a chiral center and cannot exhibit enantiomerism.

4. **2-Butanol**:
- Structure: CH3-CH(OH)-CH2-CH3
- Analysis: The second carbon (C2) has four different groups attached: a hydroxyl group (OH), a methyl group (CH3), a hydrogen (H), and an ethyl group (CH2-CH3). This carbon is a chiral center, allowing for the existence of enantiomers. Thus, 2-butanol can exhibit enantiomerism.

5. **2-Propanol**:
- Structure: CH3-CHOH-CH3
- Analysis: The carbon with the hydroxyl group (C2) is attached to two identical methyl groups (CH3). Therefore, it does not have a chiral center and cannot exhibit enantiomerism.

6. **1-Butanol**:
- Structure: CH3-CH2-CH2-CH2OH
- Analysis: Similar to 1-propanol, 1-butanol does not have a chiral center as there are no four different substituents on any carbon atom.

7. **Conclusion**:
- The only alcohol among the ones analyzed that can exhibit enantiomerism is **2-butanol** because it contains a chiral carbon atom.

### Final Answer:
The simplest alcohol that can exhibit enantiomerism is **2-butanol**.