The two compounds may be considered as :
`CH_(3)-overset(O) overset(||)(C)-underset(CH_(3)) underset(|) overset(CH_(3)) overset(|)(C)-CH_(3) and CH_(3)-overset (CH_(3))overset(|)(CH)- overset(O) overset(||)(C)-CH_(2)CH_(3)`

Options

A. position isomer
B. chain isomer
C. stereoisomer
D. tautomer

Answer

To determine the relationship between the two given compounds, we will analyze their structures step by step.

### Step 1: Identify the main chains of both compounds.
- For the first compound, we can identify the main chain as having 4 carbon atoms.
- For the second compound, the main chain consists of 5 carbon atoms.

### Step 2: Compare the number of carbon atoms in the main chains.
- The first compound has 4 carbon atoms in its main chain.
- The second compound has 5 carbon atoms in its main chain.

### Step 3: Determine the type of isomerism.
- Since the two compounds have different numbers of carbon atoms in their main chains, they cannot be positional isomers (which require the same main chain with different substituents).
- They also cannot be stereoisomers or tautomers for the same reason.
- Therefore, the only possibility left is that they are chain isomers, as they differ in the length of their carbon chains.

### Conclusion:
The two compounds can be considered as **chain isomers**.

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