Which of the following will form geometrical isomers?

Options

A.
B. `CH_(3)CH=NOH`
C.
D. all of these

Explanation

To determine which compounds can form geometrical isomers, we need to understand the conditions necessary for geometrical isomerism, specifically cis-trans isomerism. This typically occurs in compounds with restricted rotation around a double bond or in cyclic structures, where different groups can be arranged differently around the bond or ring.

### Step-by-Step Solution:

1. **Identify the Compounds**:
We need to analyze the given compounds to see if they can exhibit geometrical isomerism. The compounds mentioned are:
- 1,2-dichlorocyclobutane
- Oxyme (oxime)
- Cyclodecene

2. **Analyze 1,2-Dichlorocyclobutane**:
- This compound is a cyclic structure with two chlorine atoms attached to adjacent carbon atoms (1 and 2).
- Due to the cyclic nature, there are two possible arrangements for the chlorine atoms:
- **Cis**: Both chlorine atoms on the same side of the ring.
- **Trans**: Chlorine atoms on opposite sides of the ring.
- **Conclusion**: 1,2-dichlorocyclobutane can form geometrical isomers.

3. **Analyze Oxyme**:
- An oxime has the general structure R1R2C=NOH, where R1 and R2 can be different groups.
- The presence of a double bond between carbon and nitrogen restricts rotation, allowing for cis and trans configurations depending on the groups attached to the carbon and nitrogen.
- **Conclusion**: Oxyme can also form geometrical isomers.

4. **Analyze Cyclodecene**:
- Cyclodecene is a cyclic alkene with a double bond. The double bond can also lead to cis and trans configurations.
- Depending on the positioning of substituents around the double bond, it can exhibit both cis and trans forms.
- **Conclusion**: Cyclodecene can form geometrical isomers as well.

5. **Final Conclusion**:
- All three compounds (1,2-dichlorocyclobutane, oxyme, and cyclodecene) can form geometrical isomers.

### Final Answer:
All of the given compounds can form geometrical isomers.

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