The number of enantiomers of the compound `CH_(3)- underset(Br) underset(|)(CH)- underset(Br) underset(|)(CH)-COOH` is

Options

A. 2
B. 3
C. 4
D. 6

Answer

To determine the number of enantiomers of the compound \( CH_3-CH(Br)-CH(Br)-COOH \), we can follow these steps:

### Step 1: Identify the Structure
The compound can be represented as:
- \( CH_3 \) (methyl group)
- \( CH(Br) \) (first chiral center with a bromine substituent)
- \( CH(Br) \) (second chiral center with another bromine substituent)
- \( COOH \) (carboxylic acid group)

### Step 2: Draw the Fischer Projection
We can draw the Fischer projection of the compound to visualize its stereochemistry. The structure will look like this:
```
Br
|
CH3-CH-COOH
|
Br
```
In this representation, we can see that there are two chiral centers (the two carbon atoms that are attached to the bromine atoms).

### Step 3: Count the Chiral Centers
In the Fischer projection, we identify that there are two chiral centers:
1. The first chiral center is the carbon attached to \( CH_3 \), \( Br \), and the other \( CH \).
2. The second chiral center is the carbon attached to the other \( Br \), \( COOH \), and the adjacent \( CH \).

### Step 4: Determine the Number of Stereoisomers
The number of stereoisomers can be calculated using the formula:
\[ \text{Number of stereoisomers} = 2^n \]
where \( n \) is the number of chiral centers. Here, \( n = 2 \).

Thus, the number of stereoisomers is:
\[ 2^2 = 4 \]

### Step 5: Identify Enantiomers
Since each stereoisomer has a corresponding enantiomer, the total number of enantiomers is equal to the number of stereoisomers. Therefore, the number of enantiomers is also 4.

### Conclusion
The number of enantiomers of the compound \( CH_3-CH(Br)-CH(Br)-COOH \) is 4.

### Final Answer
The correct option is C: 4.

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