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Which of the following molecules is expe...

Which of the following molecules is expected to rotate the plane polarized light?

A

B

C

D

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The correct Answer is:
To determine which of the given molecules is expected to rotate plane-polarized light, we need to identify if the molecules are optically active. A compound is considered optically active if it meets two main criteria: 1. It must contain at least one chiral carbon atom (a carbon atom bonded to four different substituents). 2. It must not have a plane of symmetry. Let's analyze each option step by step: ### Step 1: Analyze the first molecule - Check for chiral carbon: Look for carbon atoms that are bonded to four different groups. - Check for plane of symmetry: Determine if the molecule can be divided into two symmetrical halves. **Conclusion for first molecule**: - It does not have a chiral carbon because all substituents are identical (e.g., CS2 groups). - Therefore, it cannot rotate plane-polarized light. ### Step 2: Analyze the second molecule - Identify the carbon atoms and their substituents. - Check if there is a carbon atom bonded to four different groups. **Conclusion for second molecule**: - There is a chiral carbon that is bonded to four different groups (e.g., chlorine, hydrogen, CH2, and another carbon). - There is no plane of symmetry. - Therefore, this molecule is optically active and can rotate plane-polarized light. ### Step 3: Analyze the third molecule - Again, identify the carbon atoms and their substituents. - Check for chiral carbon and plane of symmetry. **Conclusion for third molecule**: - Although there is a carbon with four bonds, there is a plane of symmetry present. - Therefore, it is not optically active and cannot rotate plane-polarized light. ### Step 4: Analyze the fourth molecule - Check for chiral carbon and plane of symmetry. **Conclusion for fourth molecule**: - The carbon atoms do not have four different substituents. - Therefore, it is not optically active and cannot rotate plane-polarized light. ### Final Answer: The second molecule is the only one that is expected to rotate plane-polarized light. ---

To determine which of the given molecules is expected to rotate plane-polarized light, we need to identify if the molecules are optically active. A compound is considered optically active if it meets two main criteria: 1. It must contain at least one chiral carbon atom (a carbon atom bonded to four different substituents). 2. It must not have a plane of symmetry. Let's analyze each option step by step: ### Step 1: Analyze the first molecule ...
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