Total number of stereoisomer possible for the compound.
`H_(3)C-CH=CH-CH=CH-CH=CH-Ph`

Explanation

To determine the total number of stereoisomers possible for the compound `H₃C-CH=CH-CH=CH-CH=CH-Ph`, we can follow these steps:

### Step 1: Identify the number of double bonds
The given compound has three double bonds. We can identify them as follows:
1. Between the first and second carbon (C1=C2)
2. Between the second and third carbon (C3=C4)
3. Between the fourth and fifth carbon (C5=C6)

So, the total number of double bonds (n) is **3**.

### Step 2: Identify the number of chiral carbons
Next, we need to check for chiral carbons in the structure. A chiral carbon is a carbon atom that is attached to four different groups. In this compound, there are no carbon atoms that meet this criterion. Therefore, the number of chiral carbons (c) is **0**.

### Step 3: Calculate the total number of stereoisomers
The total number of stereoisomers can be calculated using the formula:
\[ \text{Total Stereoisomers} = 2^{(n + c)} \]
Where:
- n = number of double bonds
- c = number of chiral carbons

Substituting the values we found:
\[ \text{Total Stereoisomers} = 2^{(3 + 0)} = 2^3 = 8 \]

### Conclusion
Thus, the total number of stereoisomers possible for the compound `H₃C-CH=CH-CH=CH-CH=CH-Ph` is **8**.

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