The end product (B) of the reaction sequence :
`C_2 H_5 - N - CH_3 underset(NaOH) overset( Ph - overset(overset(O)(||))C - CI)to A underset(H_2 O) overset(LiAIH_4) (to) B`

Options

A.
B.
C.
D.

Explanation

To solve the given problem, we will break down the reaction sequence step by step.

### Step 1: Identify the Reactants
The starting compound is an amine, specifically ethyl methyl amine, which can be represented as:
\[ C_2H_5 - N - CH_3 \]

### Step 2: Reaction with Phosgene
The first reaction involves the amine reacting with phosgene (which is represented as \( Ph - C(=O)Cl \)) in the presence of sodium hydroxide (NaOH). This reaction leads to the formation of a carbamate.

The reaction can be represented as:
\[ C_2H_5 - N - CH_3 + Ph - C(=O)Cl \xrightarrow{NaOH} Ph - C(=O) - N(C_2H_5)(CH_3) \]

This product is a carbamate derivative, which we will denote as compound A.

### Step 3: Reduction with Lithium Aluminium Hydride
Next, compound A undergoes reduction with lithium aluminium hydride (LiAlH4) in the presence of water (H2O). Lithium aluminium hydride is a strong reducing agent that can reduce the carbonyl group (C=O) of the carbamate to an alcohol.

The reaction can be represented as:
\[ Ph - C(=O) - N(C_2H_5)(CH_3) + LiAlH_4 \xrightarrow{H_2O} Ph - C(OH) - N(C_2H_5)(CH_3) \]

### Step 4: Identify the Final Product
The final product B is thus:
\[ Ph - C(OH) - N(C_2H_5)(CH_3) \]

### Conclusion
The end product B of the reaction sequence is:
\[ Ph - C(OH) - N(C_2H_5)(CH_3) \]