Which of the following sequence of reagent is the good means to furnish the conversion?
`R - CH_(2) OH to R - CH_(2) NH_(2)`

Options

A. `KMnO_(4) , SOCI_(2) , NH_(3) , Delta , NaOBr`
B. `SOCI_(2) , NaCN, H_(2) //Ni`
C. `CrO_(3)` in dilute acetone, `NH_(3) , H_(2) , Ni`
D. `Cu, 300^(@) C , NH_(2) , LiAIH_(4)`

Answer

To convert R-CH₂OH (an alcohol) to R-CH₂NH₂ (a primary amine), we can follow a series of chemical reactions. Here is a step-by-step breakdown of the process:

### Step 1: Oxidation of Alcohol
- **Reagent**: CrO₃ (Chromium trioxide)
- **Reaction**: The primary alcohol (R-CH₂OH) is oxidized to an aldehyde (R-CHO).
- **Equation**:
\[ R-CH_2OH \xrightarrow{CrO_3} R-CHO \]

### Step 2: Formation of an Amine
- **Reagent**: Ammonia (NH₃)
- **Reaction**: The aldehyde (R-CHO) reacts with ammonia (NH₃) to form an imine (R-CH=NH).
- **Equation**:
\[ R-CHO + NH_3 \rightarrow R-CH=NH + H_2O \]

### Step 3: Reduction of Imine
- **Reagent**: H₂ with Ni (Nickel catalyst)
- **Reaction**: The imine (R-CH=NH) is reduced to a primary amine (R-CH₂NH₂).
- **Equation**:
\[ R-CH=NH + H_2 \xrightarrow{Ni} R-CH_2NH_2 \]

### Final Product
- The final product after these reactions is R-CH₂NH₂, which is the desired primary amine.

### Conclusion
The sequence of reagents that effectively converts R-CH₂OH to R-CH₂NH₂ is:
1. CrO₃ (to oxidize the alcohol to an aldehyde)
2. NH₃ (to form an imine)
3. H₂ with Ni (to reduce the imine to a primary amine)