`Ph - CO - NH_(2) + Ph - CH_2 - CO - overset(15)(N) H_(2) overset(overset(Theta)(O) H + Br_(2) ) (to) A+ B`
Products A and B are :

Options

A. `Ph - NH_2`
B. `Ph - CH_2 overset(15) (N) H_2`
C. `Ph - CH_(2) - NH_(2)`
D. `Ph - overset(15) (N) H_2`

Explanation

To solve the problem, we need to analyze the reaction of the two substrates given, which are:

1. **Substrate 1**: Ph - CO - NH₂ (Phenylacetamide)
2. **Substrate 2**: Ph - CH₂ - CO - N(15)H₂ (Isotopically labeled phenylacetamide)

The reagents used in the reaction are Br₂ and OH⁻ (base), which will lead to the formation of products A and B.

### Step-by-Step Solution:

**Step 1: Analyze Substrate 1 (Ph - CO - NH₂)**

- The first substrate is phenylacetamide (Ph - CO - NH₂).
- When treated with Br₂ in the presence of a base (OH⁻), this substrate undergoes the Hofmann degradation reaction.
- In this reaction, the amide (NH₂) is converted into a primary amine, releasing carbon dioxide (CO₂).

**Product A from Substrate 1**:
- The product will be: Ph - NH₂ (aniline) + CO₂

**Step 2: Analyze Substrate 2 (Ph - CH₂ - CO - N(15)H₂)**

- The second substrate is isotopically labeled phenylacetamide (Ph - CH₂ - CO - N(15)H₂).
- Similar to the first substrate, when treated with Br₂ and OH⁻, the amide group will also undergo Hofmann degradation.
- The primary amine formed will retain the isotopic label.

**Product B from Substrate 2**:
- The product will be: Ph - CH₂ - NH₂ (isotopically labeled benzylamine) + CO₂

### Final Products:

- **Product A**: Ph - NH₂ (Aniline)
- **Product B**: Ph - CH₂ - NH₂ (Isotopically labeled benzylamine)

### Conclusion:

The products A and B are:
- A = Ph - NH₂
- B = Ph - CH₂ - NH₂