`CH_(3)-overset(O)overset(||)(C)-H` and `Ph-overset(O)overset(||)(C)-H` can be differentiated by :

Options

A. Tollen's reagent
B. Fehling's solution
C. Lucas reagent
D. Victor meyer's test

Explanation

To differentiate between acetaldehyde (CH₃CHO) and benzaldehyde (C₆H₅CHO), we can use the Fehling's solution test. Here’s a step-by-step explanation of the process:

### Step-by-Step Solution:

1. **Understanding the Compounds**:
- Acetaldehyde (CH₃CHO) is an aliphatic aldehyde, while benzaldehyde (C₆H₅CHO) is an aromatic aldehyde.

2. **Preparation of Fehling's Solution**:
- Fehling's solution consists of two solutions: Fehling's A (copper(II) sulfate solution) and Fehling's B (alkaline sodium tartrate solution). Mix equal volumes of these two solutions to prepare Fehling's solution.

3. **Testing Acetaldehyde**:
- Take a small amount of acetaldehyde and add it to the prepared Fehling's solution.
- Heat the mixture in a water bath.

4. **Observation for Acetaldehyde**:
- Upon heating, acetaldehyde will reduce the copper(II) ions (Cu²⁺) in Fehling's solution to form cuprous oxide (Cu₂O), which precipitates as a red solid.
- This indicates a positive test for reducing sugars and aldehydes.

5. **Testing Benzaldehyde**:
- Now, take a small amount of benzaldehyde and add it to another portion of the Fehling's solution.
- Again, heat the mixture in a water bath.

6. **Observation for Benzaldehyde**:
- Benzaldehyde does not reduce the copper(II) ions in Fehling's solution, so there will be no formation of red precipitate.
- This indicates a negative test for benzaldehyde.

7. **Conclusion**:
- The presence of a red precipitate indicates the presence of acetaldehyde, while the absence of a precipitate indicates benzaldehyde. Thus, these two aldehydes can be differentiated using Fehling's solution.