Which of the following compounds will not produce `CO_(2)` on reaction with `NaHCO_(3)` ?

Options

A.
B.
C.
D.

Explanation

To determine which of the given compounds will not produce carbon dioxide (CO₂) when reacted with sodium bicarbonate (NaHCO₃), we need to analyze the acidity of each compound. Sodium bicarbonate is a weak base and will react with strong acids to release CO₂. Here’s the step-by-step solution:

### Step 1: Understand the Reaction
- Sodium bicarbonate (NaHCO₃) reacts with acids to produce carbon dioxide (CO₂), water (H₂O), and a salt.
- The general reaction is:
\[ \text{Acid} + \text{NaHCO}_3 \rightarrow \text{Salt} + \text{H}_2\text{O} + \text{CO}_2 \]
- For CO₂ to be released, the acid must be strong enough to donate a proton (H⁺) to NaHCO₃.

### Step 2: Analyze Each Compound
1. **Benzene Sulfonic Acid (Option A)**:
- This is a strong acid. Its conjugate base is stabilized by resonance and electron-withdrawing effects from the sulfonyl group.
- **Conclusion**: It will produce CO₂ with NaHCO₃.

2. **Phenol (Option B)**:
- Phenol is a weak acid. Its acidity is lower compared to the other compounds listed. It does not release enough H⁺ to react with NaHCO₃ effectively.
- **Conclusion**: It will **not** produce CO₂ with NaHCO₃.

3. **Benzoic Acid (Option C)**:
- Benzoic acid is a strong acid. Its conjugate base (benzoate ion) is stabilized by resonance.
- **Conclusion**: It will produce CO₂ with NaHCO₃.

4. **Squaric Acid (Option D)**:
- Squaric acid is also a strong acid. Its conjugate base is stabilized by resonance.
- **Conclusion**: It will produce CO₂ with NaHCO₃.

### Final Answer
The compound that will **not** produce CO₂ on reaction with NaHCO₃ is **Option B: Phenol**.