Which of the following compounds will react with `NaNH_(2)` ?

Options

A. `CH_(3)-C-=CH`
B.
C.
D. `ph-overset(O)overset(||)underset(O)underset(||)(S)-OH`

Explanation

To determine which of the given compounds will react with sodium amide (NaNH₂), we need to understand the nature of sodium amide as a strong base and its ability to deprotonate compounds that have acidic hydrogen atoms. Here’s a step-by-step solution:

### Step 1: Identify the Nature of Sodium Amide
Sodium amide (NaNH₂) is a strong base. It can abstract acidic protons (H⁺ ions) from compounds that possess acidic hydrogen atoms.

### Step 2: Analyze Each Compound
We will analyze each of the given compounds to see if they contain acidic hydrogen atoms that can be abstracted by NaNH₂.

1. **Compound A: Alkyne (e.g., terminal alkyne)**
- Terminal alkynes have a hydrogen atom attached to a carbon that is part of a triple bond (C≡C-H). This hydrogen is acidic and can be easily abstracted by NaNH₂ to form an acetylide ion.
- **Conclusion**: Reacts with NaNH₂.

2. **Compound B: Carboxylic Acid**
- Carboxylic acids (RCOOH) have a hydrogen atom attached to the hydroxyl group (-OH), which is acidic. NaNH₂ can deprotonate this hydrogen, forming a carboxylate ion.
- **Conclusion**: Reacts with NaNH₂.

3. **Compound C: Phenolic Compound (e.g., p-nitrophenol)**
- Phenolic compounds have an -OH group attached to a benzene ring. The hydrogen of the hydroxyl group is slightly acidic due to resonance stabilization. NaNH₂ can abstract this hydrogen.
- **Conclusion**: Reacts with NaNH₂.

4. **Compound D: Sulfonic Acid**
- Sulfonic acids (R-SO₃H) are stronger acids than carboxylic acids. The hydrogen atom attached to the sulfonic group is highly acidic and can be abstracted by NaNH₂.
- **Conclusion**: Reacts with NaNH₂.

### Step 3: Final Conclusion
All four compounds (A, B, C, and D) have acidic hydrogen atoms and will react with sodium amide (NaNH₂).

### Summary of Results
- **Compound A**: Reacts with NaNH₂ (terminal alkyne).
- **Compound B**: Reacts with NaNH₂ (carboxylic acid).
- **Compound C**: Reacts with NaNH₂ (phenolic compound).
- **Compound D**: Reacts with NaNH₂ (sulfonic acid).

### Final Answer
**All options (A, B, C, and D) will react with NaNH₂.**

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