Which of the following will not give white precipitate with
ammoniacal silver nitrate solution ?

Options

A. `CH_(3)-C-=C-CH_(3)`
B.
C.
D.

Explanation

To determine which of the following compounds will not give a white precipitate with ammoniacal silver nitrate solution, we need to analyze the types of compounds involved. The ammoniacal silver nitrate solution is commonly used to test for terminal alkynes, which contain an acidic hydrogen atom.

### Step-by-Step Solution:

1. **Identify the Types of Compounds**:
- We need to identify the compounds given in the question. Let's denote them as Compound A, Compound B, Compound C, and Compound D.

2. **Understand the Reaction**:
- Ammoniacal silver nitrate (Ag(NH3)2NO3) reacts with terminal alkynes to form a white precipitate of silver acetylide.
- Terminal alkynes have the general formula R-C≡C-H, where R is any alkyl or aryl group. The hydrogen atom attached to the carbon of the triple bond is acidic and can react with the silver ion to form a precipitate.

3. **Analyze Each Compound**:
- **Compound A**: If this is an internal alkyne (R-C≡C-R'), it does not have an acidic hydrogen and will not react to form a precipitate.
- **Compound B**: If this is also an internal alkyne, it will similarly not give a precipitate.
- **Compound C**: If this is an alkene (R-CH=CH-R'), it also lacks an acidic hydrogen and will not react to form a precipitate.
- **Compound D**: If this is a terminal alkyne (R-C≡C-H), it will react and form a white precipitate.

4. **Conclusion**:
- Based on the analysis, Compound A, Compound B, and Compound C will not give a white precipitate with ammoniacal silver nitrate solution. Therefore, the answer to the question is that these compounds do not react, while the terminal alkyne does.

### Final Answer:
The compounds that will not give a white precipitate with ammoniacal silver nitrate solution are **Compound A, Compound B, and Compound C**.