From the following sequence of reactions,
[A] `(C_(6)H_(12))overset(HCl)(to)(B)(C_(6)H_(13)Cl)+(C)(C_(6)H_(13)Cl)` react with `AgNO_(3)` to give white ppt.
[B] `overset(Alc. KOH)(to)` (D) (An isomer of A) gives positive test with `Br_(2)//C Cl_(4)`
[D] `overset("Ozonolysis")(to)` (E) gives positive iodoform test and negative Fehling's test .
[A] `overset("Ozonolysis")(to)(F)+(G)` both F and G give positive Tollen's test.
`[F]+[G]overset(Conc. NaOH)underset(Delta)(to)HCOONa+"alcohol"`
The reaction involve in the F and G with the NaOH is :

Options

A. Reimer-Tiemann reaction
B. Aldol condensation
C. Cannizzaro reaction
D. Perkin reaction

Answer

To solve the question regarding the sequence of reactions involving organic compounds, we will break down the steps systematically.

### Step-by-Step Solution:

1. **Identify Compound A**:
- Compound A is given as \(C_6H_{12}\). We need to determine its structure. The formula indicates that it has one degree of unsaturation (double bond equivalent = 1), which means it could either be a cyclic compound or have a double bond.

2. **Reaction of A with HCl**:
- When \(C_6H_{12}\) reacts with HCl, it forms compound B, which is \(C_6H_{13}Cl\). This indicates that A is likely an alkene, and the addition of HCl results in the formation of an alkyl halide (B).

3. **Formation of Isomers**:
- The reaction produces two isomers of \(C_6H_{13}Cl\) (compound B). This suggests that the addition of HCl can lead to different structural arrangements.

4. **Reaction of B with AgNO3**:
- The compound B reacts with AgNO3 to give a white precipitate, indicating that B is likely a primary or secondary alkyl halide, which can undergo nucleophilic substitution.

5. **Formation of Compound D**:
- Compound B, when treated with alcoholic KOH, undergoes elimination to form compound D, which is an isomer of A. Since D gives a positive test with Br2/CCl4, it indicates that D is likely an alkene.

6. **Ozonolysis of D**:
- The ozonolysis of compound D yields compounds F and G. Since D gives a positive iodoform test and negative Fehling's test, it suggests that D has a methyl ketone or an aldehyde structure.

7. **Ozonolysis Products F and G**:
- The ozonolysis of D breaks the double bond and forms two carbonyl compounds (aldehydes or ketones), which are F and G. Both F and G give positive Tollen's test, indicating that they are aldehydes.

8. **Reaction of F and G with Concentrated NaOH**:
- The reaction of F and G with concentrated NaOH under heating leads to the formation of HCOONa (sodium formate) and an alcohol. This suggests that one of the compounds is oxidized to form a carboxylic acid salt, while the other is reduced to form an alcohol.

9. **Identify the Type of Reaction**:
- The reaction between F and G with NaOH is indicative of the Cannizzaro reaction, where one aldehyde is oxidized to a carboxylic acid and the other is reduced to an alcohol.

### Conclusion:
The reaction involved in the interaction of compounds F and G with concentrated NaOH is the **Cannizzaro reaction**.