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The number of solution of sin^7x+cos^7x=...

The number of solution of `sin^7x+cos^7x=1 , x in [0,4pi]`

A

7

B

11

C

9

D

5

Text Solution

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The correct Answer is:
To find the number of solutions for the equation \( \sin^7 x + \cos^7 x = 1 \) in the interval \( x \in [0, 4\pi] \), we can follow these steps: ### Step 1: Analyze the Equation We start with the equation: \[ \sin^7 x + \cos^7 x = 1 \] We know that both \( \sin^2 x \) and \( \cos^2 x \) are always less than or equal to 1. Therefore, \( \sin^7 x \) and \( \cos^7 x \) will also be less than or equal to \( \sin^2 x \) and \( \cos^2 x \) respectively. ### Step 2: Establish Upper Bound From the properties of sine and cosine, we have: \[ \sin^2 x + \cos^2 x = 1 \] Thus: \[ \sin^7 x \leq \sin^2 x \quad \text{and} \quad \cos^7 x \leq \cos^2 x \] Adding these inequalities gives: \[ \sin^7 x + \cos^7 x \leq \sin^2 x + \cos^2 x = 1 \] This shows that \( \sin^7 x + \cos^7 x \) can never exceed 1. ### Step 3: Determine Conditions for Equality For \( \sin^7 x + \cos^7 x = 1 \) to hold, either \( \sin^7 x = 1 \) and \( \cos^7 x = 0 \) or \( \sin^7 x = 0 \) and \( \cos^7 x = 1 \). 1. **Case 1**: \( \sin^7 x = 1 \) - This implies \( \sin x = 1 \). - The solutions for \( \sin x = 1 \) in the interval \( [0, 4\pi] \) are: \[ x = \frac{\pi}{2} + 2k\pi, \quad k \in \mathbb{Z} \] - For \( k = 0 \): \( x = \frac{\pi}{2} \) - For \( k = 1 \): \( x = \frac{\pi}{2} + 2\pi = \frac{5\pi}{2} \) - Thus, we have 2 solutions from this case. 2. **Case 2**: \( \cos^7 x = 1 \) - This implies \( \cos x = 1 \). - The solutions for \( \cos x = 1 \) in the interval \( [0, 4\pi] \) are: \[ x = 2k\pi, \quad k \in \mathbb{Z} \] - For \( k = 0 \): \( x = 0 \) - For \( k = 1 \): \( x = 2\pi \) - For \( k = 2 \): \( x = 4\pi \) - Thus, we have 3 solutions from this case. ### Step 4: Count Total Solutions Now, we combine the solutions from both cases: - From Case 1: 2 solutions (\( \frac{\pi}{2}, \frac{5\pi}{2} \)) - From Case 2: 3 solutions (\( 0, 2\pi, 4\pi \)) Adding these gives us: \[ 2 + 3 = 5 \text{ solutions} \] ### Conclusion The total number of solutions to the equation \( \sin^7 x + \cos^7 x = 1 \) in the interval \( [0, 4\pi] \) is **5**.
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