In a condition of minimum deviation `mu = sqrt(3)`. Angle of incidence = 2 x angle of refraction then find angle of prism.

An equilateral prism is placed on the prism table of a spectrometer in the position of minimum deviation. If the angle of incidence is 60º, the angle of deviation of the ray is :

A ray of light passing through a prism (mu = sqrt3) suffers minimum deviation. It is found that the angle of incidence is double the angle of refraction within the prism. Then, the angle of prism is ________ (in degrees)

A ray of light passing through a prism having refractive index sqrt2 suffers minimum deviation. It is found that the angle of incidence is double the angle of refraction within the prism. What is the angle of prism?

If a prism having refractive index sqrt 2 has angle of minimum deviation equal to the angle of refraction of the prism, then the angle of refraction of the prism is:

In the minimum deviation position of a prism how are angle of incidence and angle of emergence related ?

A ray of light suffers minimum deviation through a prism of refractive index sqrt(2) . What is the angle of prism if the angle of incidence is double the angle of refraction within the prism?

When an equilateral prism is placed in the position of minimum deviation , the incident ray makes an angle of 37^(@) with the refracting surface . What is the material of the prism , if the angle of 37^(@) with the refracting surface . What is the angle of minimum deviation ?

A 60^@ prism has a refractive index of 1.5 . Calculate (a) the angle of incidence for minimum deviation (b) angle of minimum deviation ( c) the angle of emergence of light at maximum deviation (d) angle of maximum deviation.