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f A and B are square matrices of the sam...

f A and B are square matrices of the same order such that AB = BA, then prove by induction that `AB^n = B^nA` Further, prove that `(AB)^n = A^nB^n` for all `n in N`

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The correct Answer is:
P.M.I., the result is true for all ` n in N`
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