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If A = [[0,-tan alpha/2],[tan alpha/2,0]...

If `A = [[0,-tan alpha/2],[tan alpha/2,0]]` and I is the identity matrix of order 2, show that `I + A = (I - A)[[cos alpha,-sin alpha],[sin alpha,cos alpha]]`

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The correct Answer is:
`I + A = (I - A) [(cos alpha, - sin alpha),(sin alpha, cos alpha)]`
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