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A bag consists of 10 balls each marked w...

A bag consists of 10 balls each marked with one of the digits 0 to 9. If four balls are drawn successively with replacement from the bag, what is the probability that none is marked with the digit 0?

Text Solution

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The correct Answer is:
`1xx((9)/(10))^(4)=((9)/(10))^(4)`
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