Calculate the Coulomb's force between two `alpha` - particles separated by a distance of `3.2 xx 10^(-15)` m.

Explanation

For `alpha` - particles, we have
`q_1 =q_2 = 2e = 2 xx 1.6 xx10^(-19)C`
`r=3.2 xx10^(-15)m`
`F =1/(4piin_0)(q_1q_2)/r^2`
`F = 9 xx10^9 xx((2xx1.6 xx10^(-19))^2)/((3.2 xx10^(-15))^2)`
`F = 9 xx10^(9) xx (4xx2.56 xx10^(-38))/(10.24 xx10^(-30))`
`F = 9 xx10^(1) = 90N`
`F = 90 N`