Ten electrons have been removed from each atom to form ions. Find the electrostatic force between two such ions when separated by a distance of 4A in a medium of dielectric constant 4.

Explanation

When ten electrons are removed from an atom, then charge on each atom is
`q = 10 e = 10 xx1.6 xx10^(-19)C`
So `q_1= q_2 = q = 10 xx1.6 xx10^(-19)C`
`r = 4 Å = 4 xx10^(-10)m`
and dielectric constant , K = 4
`F=1/K(1)/(4piin_0)(q_1q_2)/(r^2)`
`F=1/K1/(4piin_0)(q^2)/r^2`
`=1/4 xx9 xx10^(9) xx((10xx1.6xx10^(-19))^2)/((4xx10^(-10))^2)`
`=1/4 xx9xx10^(9)xx(100xx2.56 xx10^(-38))/(16 xx10^(-20))`
`= 3.6 xx10^(-9)`
`=3.6 xx10^(-8)N`