Calculate the Coulomb's force between proton and electron separated `0.8 xx 10^(-15) m.`

Explanation

Charge on proton `= q_1 = 1.6 xx 10^(-19) C`
Charge on electron = `q_2 =-1.6 xx10^(-19)C`
Distance between proton and electron `= r = 0.8 xx 10^(-15) m`
`F=1/(4piin_0)(q_1q_2)/(r^2)`
`= 9 xx10^9 xx((1.6 xx10^(-19))xx(-1.6xx10^(-19)))/((0.8 xx10^(-15))^2)`
`F=-9xx10^9 xx((1.6xx10^(-19))^2)/((0.8xx10^(-15))^2)`
`= (9 xx1.6 xx1.6)/(0.8 xx0.8)xx10^(9-38+30) `
= `- 36 xx10^1`
`F = - 360 N`
Here, negative sign shows that force between proton and electron is attractive.