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A box encloses an electric dipole of 3 m...

A box encloses an electric dipole of `3 mu C and - 3 C`, if the dipole length is 6 cm, then find total electric flux associated with box.

Text Solution

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Net charge of dipole `q = - 3 + 3 = 0`
As the net charge enclosed by the box is zero
`therefore phi = (q)/(epsilon_(0)) = (0)/(epsilon_(0)) = 0 `
So total electric flux associated with the box is zero.
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