At a point due to a point charge, the values of electric field intensity and potential are `32NC^-1` and `16JC^-1` respectively. Calculate magnitude of charge and distance of the charge from the point of observation.

Explanation

Let q is the given charges r = distance of observation point from charge q.
Then Electric field intensity `=E=(1)/(4pi epsi_(0))(q)/(r^(2))=32" "….(1)`
`:. E=32 NC^(-1)` (given)
Also Electric Potential `=V=16 JC^(-1)`
`rArr (1)/(4pi epsi_(0))(q)/(r)=16 " "...(2)`
Dividing eqn (1) by eqn (2).
`((1)/(4pi epis_(0))(q)/(r^(2)))/((1)/(4piepsi_0)(q)/(r))=(32)/(16)`
`rArr (1)/(r)=2`
`rArr r=(1)/(2)=0.5m`
Putting value of r in eq. (2).
`9xx10^(9)xx(q)/(0*5)=16`
`q=(0*5xx16)/(9xx10^(9))`
`q=8*89xx10^(-10)C`