A 12pF capacitor is connected to a 50V battery. How much electrostatic energy is stored in the capacitor?

Explanation

`C =12 PF = 12 xx 10^(-12) F`
V = 50 V
Energy stored in the capacitor `=1/2 CV^(2)`
`=1/2 xx 12 xx 10^(-12) xx (50)^(2)`
`= 6 xx 10^(-12) xx 25 xx 10^(2)`
`=1.50 xx 10^(-10)`
`=1.50 xx 10^(-8) J`