A potential difference of 3V is applied across a conductor of resistance 1.5 Omega.
Calculate the number of electrons flowing through it in one second. Given charge on electron, `e=1.6 xx10^(-19)C.`

Explanation

V = 3 V
`R = 1. Omega`
Numebr of electrons = n = ?
t = 1 s
`I =q/t=V/R`
`("ne")/(t)=V/R" " [:. q = "ne"]`
`implies (nxx1.6 xx10^(-19))/(1)=3/(1.5)`
`implies n = (3)/(1.6) xx10^(-19)`
`implies n = 1.25 xx10^(19)`