60 W-220 V bulb and 100 W-200 V bulb are connected in parallel to main supply. Which bulb will draw more current ?

Explanation

For bulb - I :
P = 60 W
`V_1 = 60 W`
`V_1 =220` Volt
`R_(1) = V_(1)^2/P_(1) = (220xx220)/60`
`implies R = 806.67 Omega`
For bulb - II :
`P_(2) = 100 W `
`V_2 = 200 W`
`R_(2) = V_(2)^2/P_(2) = (220xx220)/100`
`implies R = 484 Omega`
`:. R_2 lt R_1`
So Bulb (100 W, 220 V) will withdraw more current .