A wire of length 2.0 m, diameter 1.0 mm has `50 xx 10^(-3)Omega` (ohm) resistance. Calculate the resistivity of the material of the wire.

Explanation

Length of wire = l = 2.0 m
Diameter of the wire = 1.0 mm
Radius of the wire `=r=1/2=0.5mm`
`r =0.5 xx10^(-3) m = 5 xx10^(-4)m`
Resistance of the wire `= R= 50 10^(-3)Omega`
Resistivity of the material of wire = l = ?
`R= rho (l)/A`
`implies rho=(50xx10^-3)/(2) xx22/7 xx(5xx10^(-4))^2`
`implies rho = 64.3 xx10^(-11)Omegam`
`implies rho=1.9643 xx10^(-8)Omegam`
`implies rho=1.96xx10^(-8)Omegam`