Awire with ana area of cross section as `10 mm^2` has resistance of `5 Omega` when a potential difference across its ends is 25 V. calculate the drift velocity of electrons. Given the number density of electron as `5 xx10^20` electrons per cubic meter `(em^-3)`

Explanation

`A = 10mm^2 = 10 xx 10^(-6)m^2`
R = 5
V = 25V
Drift velocity `= V_d=2`
`n = 5 xx 1020 " electrons/m"^3`
V = IR
`I=V//R=25/5=5A`
`I=nAeV_d`
`V_d=I/(nAe)=5/(5xx10^(20)xx10xx10^(-5)xx1.6xx10^(-19))`
`V_d=10^4/(1.6)=10/(1.6)xx10^3 =6.25xx10^3 m//s`