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A 2 MeV proton is moving perpendicular t...

A 2 MeV proton is moving perpendicular to a uniform magnetic field o 2.5 tesla. The force on the proton is

Text Solution

Verified by Experts

Here, `B= 2.5 T, `
Mass of proton, `m= 1.65 xx 10^(-27) kg`
and KE of proton = 2 MeV
`= 2 xx 10^(-6) xx 1.6 xx 10^(-19)J`
`(because 1 MeV = 10^6 xx 1.6 xx 10^(-19) J)`
`therefore 1/2 mv^2 = 2 xx 10^6 xx 1.6 xx 10^(-19)`
`= 1/2 xx 1.65 xx 10^(-27) xx v^2`
`= 2 xx 10^6 xx 1.6 xx 10^(-19)`
`v = sqrt((2 xx 2 xx 10^6 xx 1.6 xx 10^(-19))/(1.65 xx 10^(-27)))`
`= 1.97 xx 10^(7) ms^(-1)`
`therefore F_m = qv sin theta`
`= 1.6 xx 10^(-19) xx 1.97 xx 10^7 xx 2.5 xx sin 90^@ N`
`= 7.88 xx 10^(-12)N`
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