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A Sobnoid of length 50cm, having 100 tur...

A Sobnoid of length 50cm, having 100 turns Carries a Current of 2.5A. Find the magnetic field (B), (a) in the interior of sobnoid (b) at one end of the sobnoid.
Give `mu = 4 xx 10^(-7) wb A^(-1)M^(-1)`

Text Solution

Verified by Experts

length = `l = 50 cm = 1/2 m `
Number of turns = `N = 100 `
`I = 2.5 A `
(a) In the interior of sobnoid = `B = mu N/l I`
`= 4pi xx 10^(-7) xx 100/(1//2) xx 2.5`
`= 2pi xx 10^(-4)`
`= 6.28 xx 10^(-4) T`
(b) At one end of sobnoid `= B. = 1/2 B`
`B. = 1/2 xx 6.28 xx 10^(-4)`
`B. = 3.14 xx 10^(-4) T`
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