A coil of inductance 0.50 H and resistance `100 Omega` is connected to a 240 V, 50 Hz ac supply. What is the maximum current in the coil?

Explanation

L= 0.4 H
`R= 100Omega`
`E_v= 400 V`
`v= 50 Hz `
`I_0 =?`
`Z= sqrt(R^2 +(2pivL)^(2))`
`Z=sqrt((100)^2+(2xx3.14xx50xx0.4)^(2))`
`Z = sqrt(10000+(125.6)^(2))`
`Z = sqrt(10000+15775.36)`
`Z = sqrt(25775.36)`
`Z=160.55Omega`
`I_v =E_v/Z = 400/(160.55)=2.49A`
`I_v=I_0/sqrt2`
Maximum value of current in the coil `= I_0 = sqrt2I_v`
`I_0 = 1.414 xx 2.49`
`I_0 = 3.52 A`