A capacitor of capacitance `100 muF` and a coil of resistance `50 Omega` and inductance 0.5 H are connected in series with a 110 V, 50 Hz AC source. Find the rms value of the current.

Explanation

`C = 100 muF = 100 xx 10^(-6)F = 10^(-4)F`
`R = 50 Omega`
`L = 0.5 H`
`E_v = 110V`
Frequency = v= 50 Hz
Impedance = Z= ?
`Z=sqrt(R^2+(X_L-X_C)^(2))`
`Z=sqrt(R^2+(2pivL-1/(2pivC))^(2))`
`Z=sqrt((50)^(2)+(2xx3.14xx50xx0.5-1/(2xx3.14xx50xx10^(-4)))^(2))`
`Z =sqrt(2500+(157-31.84)^(2))`
`= sqrt(2500+(125.16)^(2))`
`= sqrt(2500+15665.03)`
`Z = 134.77Omega`