Find wavelength of electromagnetic waves of frequency `5 xx 10^(19)Hz` in free space. Give its two applications.

Explanation

Wavelength `=lamda=?`
Frequency `=v=5xx10^(19)` Hz
Velocity of electromagnetic waves
`=C=3xx10^(8)" ms"^(-1)`
`C=lamdav`
`lamda=(C)/(v)`
`lamda=(3xx10^(8))/(5xx10^(19))`
`lamda=0*6xx10^(-11)`m
`lamda=6xx10^(-12)` ,
Applications : See Very Short answer Type Question No. 18 (1 Mark).