Find the wavelength of electromagnetic waves of frequency `6 xx 10^(12)Hz` in free space. Give its two applications.

Explanation

Wavelength `=lamda=?`
Frequency `=v=6xx10^(12)` Hz
Velocity of electromagnetic waves
`=C=3xx10^(8)" ms"^(-1)`
`C=lamdav`
`lamda=(C)/(v)`
`lamda=(3xx10^(8))/(6xx10^(12))`
`lamda=0*5xx10^(-4)`m
`lamda=50xx10^(-6)m=50mu m`.
Applications : See Very Short Answer Type Question No. 7 (1 Mark).