Light of wavelength `5,000 overset @A` is incident on a double slit.If the overall separation of 10 fringes on a screen 200 cm away is 1.0 cm,find the distance between the two slits.

Explanation

Wavelength `=lambda = 5000 A`
`=5000 xx 10^(-10) m = 5 xx 10^(-7) m`
Distance of screen from slit =D = 200 cm= 2m Overall separation of 10 fringes is 1.0 cm `rArr 10beta = 1`
`beta = 1/10 = 0.1 cm`
`=0.1 xx 10^(-2) m = 10^(-3) m`
Distance between slits = d= ?
`beta = (lambdaD)/d`
`d = (lambdaD)/beta`
`d = (5 xx 10^(-7) xx 2)/10^(-3)`
` d= 10^(-3) m = 1 mm`
d = 1mm