Calculate the wavelength of a photon of energy `10^10 eV` (electron volt). Given Planck's constant `h = 6.62 xx 10^(-34) Js`, (Joule second)

Explanation

`lambda= ?`
`E = 10^10 eV = 10^(10) xx 1.6 xx 10^(-19) J`
`E = (hc)/(lambda)`
`lambda = (6.62 xx 10^(-34) xx 3 xx 10^(8))/(1.6 xx 10^(-9))`
`lambda = 12.41 xx 10^(-17)`
`lambda = 12.41 xx 10^(-17)`
`lambda = 1.241 xx 10^(-16) m`