Electron and proton are moving with the same speed, which will have more wvalength?

Explanation

We know `lamda= (h)/(mv)`
Wavelength of moving electron `=lamda_(e )= (h)/(m_(e ) v_(e ))`
Wavelength of moving proton `=lamda_(p)= (h)/(m_(p) v_(p))`
`(lamda_(e ))/(lamda_(p))= (h)/(m_(e) v_(e)) xx (m_(p) v_(p))/(h)`
`(lamda_(e ))/(lamda_(p)) = (m_(p))/(m_(e )) ((v_(p))/(v_(e )))`
But `v_(p)= v_(e )`
`therefore (lamda_(e))/(lamda_(p))= (m_(p))/(m_(e ))`
Because `m_(p) gt m_(e)`
`therefore lamda_(e) gt lamda_(p)`
So electron has larger wavelength than proton.