Calculate the de-Broglie wavelength for electron moving with speed of `6 xx 10^5 m s^(-1)`.

Explanation

Mass of electron `=m = 9.1 xx 10^(-31)kg`
`v= 6 xx 10^(5) ms^(-1)`
de-broglie wavelength for electron `=lamda`=?
`lamda= (h)/(mv)`
`=(6.62 xx 10^(-34))/(9.1 xx 10^(-31) xx 6 xx 10^(5))`
`=0.1212 xx 10^(-8)`
`=1.212 xx 10^(-9)m`
`=1.212 nm`