A photon and an electron have got same de Brogile wavelength. Which has greater total energy? Explain.

Explanation

We know `lamda= (h)/(sqrt(2mE))`
where E is K.E of the particle
On squaring `lamda^(2)= (h^(2))/(2mE)`
`E= (h^(2))/(2m lamda^(2))`
`E prop (1)/(m)`
As mass of electron is smaller than proton, so kinetic energy of electron is more than that of proton.