Calculate momentum of electron, if their wavelength is `1overset @ A`. Given, Planck's constant `h=6.625 xx 10^(-34) Js`, mass of electron `m=9.1 xx 10^(-31)`kg.

Explanation

Momentum of electron = P= ?
`lamda= 1 Å=10^(-10)m`
`h= 6.626 xx 10^(-34) Js`
`m=9.1 xx 10^(-31)kg`
`P= (h)/(lamda)`
`P= (6.626 xx 10^(-34))/(10^(-10))`
`=6.626 xx 10^(-24) kg m//s`