Calculate the momentum of electrons, if their wavelength is `3 Å`. Given that Planck's constant, `h= 6.626 xx 10^(-34) Js`, mass of electron, `m=9.1 xx 10^(-31)kg.`

Explanation

Momentum of electron = P=? `lamda= 3Å =3 xx 10^(-10)m`
`h= 6.626 xx 10^(-34)Js`
`m= 9.1 xx 10^(-31)kg`
`P = (h)/(lamda)= (6.626 xx 10^(-34))/(3 xx 10^(-10))`
`P= 2.208 xx 10^(-24)kg m//s`