Calculate the de-Bronglie waveelngth for electron and protonif their speed is `10^5 m s^(-1)` .Given,mass of an electron `=9.1 xx 10^(-31) kg`,mass of proton = `1.67 xx 10^(-27) kg` and Planck's constant = `6.62 xx 10^(-34) J s`.

Explanation

Mass of electron `=m_(e) = 9.1 xx 10^(-31)kg`
Mass of proton =`m_(p) = 1.67 xx 10^(-27)kg`
Wavelength of electron `=lamda_(e)=`? Wavelength of proton `=lamda_(p)`= ?
Velocity of electron = Velocity of proton = `v=10^(5) m//s`
`lamda_(e)= (h)/(m_(e )V)= (6.625 xx 10^(-34))/(9.1 xx 10^(-31) xx 10^(5))`
`=7.28 xx 10^(-8)`
`lamda_(e)= 7.28 xx 10^(-9) = 7.28nm`
and `lamda_(p)= (h)/(m_(p) v)= (6.625 xx 10^(-34))/(1.67 xx 10^(-27) xx 10^(5))`
`=3.97 xx 10^(-12)m`
`lamda_(p)= 3.97` pm